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fix: PostgreSQL的SQL脚本在非多租户模式下部份表tanant_id默认值缺失造成错误

zheng decan 2 years ago
parent
commit
5c6451f6aa
1 changed files with 5 additions and 5 deletions
  1. 5 5
      sql/postgresql/ruoyi-vue-pro.sql

+ 5 - 5
sql/postgresql/ruoyi-vue-pro.sql

@@ -2493,7 +2493,7 @@ CREATE TABLE "system_login_log" (
   "id" int8 NOT NULL,
   "log_type" int8 NOT NULL,
   "trace_id" varchar(64) COLLATE "pg_catalog"."default" NOT NULL,
-  "user_id" int8 NOT NULL,
+  "user_id" int8 NOT NULL DEFAULT 0,
   "user_type" int2 NOT NULL,
   "username" varchar(50) COLLATE "pg_catalog"."default" NOT NULL,
   "result" int2 NOT NULL,
@@ -2866,7 +2866,7 @@ CREATE TABLE "system_oauth2_access_token" (
   "updater" varchar(64) COLLATE "pg_catalog"."default",
   "update_time" timestamp(6) NOT NULL,
   "deleted" int2 NOT NULL DEFAULT 0,
-  "tenant_id" int8 NOT NULL,
+  "tenant_id" int8 NOT NULL DEFAULT 0,
   "scopes" varchar(255) COLLATE "pg_catalog"."default" DEFAULT ''::character varying
 )
 ;
@@ -2909,7 +2909,7 @@ CREATE TABLE "system_oauth2_approve" (
   "updater" varchar(64) COLLATE "pg_catalog"."default",
   "update_time" timestamp(6) NOT NULL,
   "deleted" int2 NOT NULL DEFAULT 0,
-  "tenant_id" int8 NOT NULL
+  "tenant_id" int8 NOT NULL DEFAULT 0
 )
 ;
 COMMENT ON COLUMN "system_oauth2_approve"."id" IS '编号';
@@ -3011,7 +3011,7 @@ CREATE TABLE "system_oauth2_code" (
   "updater" varchar(64) COLLATE "pg_catalog"."default",
   "update_time" timestamp(6) NOT NULL,
   "deleted" int2 NOT NULL DEFAULT 0,
-  "tenant_id" int8 NOT NULL
+  "tenant_id" int8 NOT NULL DEFAULT 0
 )
 ;
 COMMENT ON COLUMN "system_oauth2_code"."id" IS '编号';
@@ -3053,7 +3053,7 @@ CREATE TABLE "system_oauth2_refresh_token" (
   "updater" varchar(64) COLLATE "pg_catalog"."default",
   "update_time" timestamp(6) NOT NULL,
   "deleted" int2 NOT NULL DEFAULT 0,
-  "tenant_id" int8 NOT NULL,
+  "tenant_id" int8 NOT NULL DEFAULT 0,
   "scopes" varchar(255) COLLATE "pg_catalog"."default" DEFAULT ''::character varying
 )
 ;